Synthesis of Ozanimod Hydrochloride

Synthesis of Ozanimod Hydrochloride

Ozanimod Hydrochloride is prepared from the eastern fragment joined to the western fragment to form a central oxadiazole ring and through a chemical reaction. The specific synthesis steps are as follows:

Step 1: Preparation of Eastern Fragment

Protection of the ketone 184 furnished cyclic ketal 185 in 62% yield. Treatment with hydroxylamine hydrochloride afforded eastern fragment 186 in quantitative yield.

Step 1: Preparation of Ozanimod Hydrochloride

Next, carboxylic acid 187 (western fragment) was activated with CDI and coupled with eastern fragment 186 to form oxadiazole 189. The crude material was used without further purification in the subsequent ketal deprotection, which delivered ketone 190 in 76% yield from 187. Condensation of ketone 190 with 2-aminoethanol under DeanStark conditions afforded imine 191 in 96% yield. Chiral ruthenium complex 192 catalyzes the reduction of imine 190 to ozanimod 193 in high enantiomeric excess. Finally, salt formation with methanolic HCl produces ozanimod hydrochloride in excellent yield.